android - How to start app from first when home button is clicked -

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in application when click home button , when again when open app should come first.i having splash screen first activity.when open app,the app should start splash screen.

         @override     public void onattachedtowindow() {         super.onattachedtowindow();         this.getwindow().settype(windowmanager.layoutparams.type_keyguard);                }     @override     public boolean onkeydown(int keycode, keyevent event) {        if(keycode == keyevent.keycode_home)        {         log.i("home button","clicked");           onpause();        }     return false;          }     protected void onpause() {          super.onpause();          intent i=new intent(h2.this,homeexampleactivity.class);         startactivity(i);         // start first activity      }

i tried in way overriding on pause method not working.please me how solve issue

you can try this:

 boolean hasgone = false;   @override  void onresume() {   super.onresume();     if(hasgone){           intent intent = new intent(h2.this, homeexampleactivity.class);       intent.setflags(intent.flag_activity_clear_top);       startactivity(intent);   }  }   @override  void onpause() {      super.onpause();       hasgone = true;   }

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