python - Split string based on a regular expression -

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i have output of command in tabular form. i'm parsing output result file , storing in string. each element in 1 row separated 1 or more whitespace characters, i'm using regular expressions match 1 or more spaces , split it. however, space being inserted between every element:

>>> str1="a    b     c      d" # spaces irregular >>> str1 'a    b     c      d' >>> str2=re.split("( )+", str1) >>> str2 ['a', ' ', 'b', ' ', 'c', ' ', 'd'] # 1 space element between!!!

is there better way this?

after each split str2 appended list.

by using (,), capturing group, if remove them not have problem.

>>> str1 = "a    b     c      d" >>> re.split(" +", str1) ['a', 'b', 'c', 'd']

however there no need regex, str.split without delimiter specified split whitespace you. best way in case.

>>> str1.split() ['a', 'b', 'c', 'd']

if wanted regex can use ('\s' represents whitespace , it's clearer):

>>> re.split("\s+", str1) ['a', 'b', 'c', 'd']

or can find non-whitespace characters

>>> re.findall(r'\s+',str1) ['a', 'b', 'c', 'd']

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