java - How can I check keyboard for a single press? -

-

i can't figure how condition work. there keyboard.iskeydown(//anykey) condition?

import org.lwjgl.input.keyboard; import org.lwjgl.input.mouse;  public class inputhandler {      public static boolean currentkeystate, previouskeystate;      public static void update() {         previouskeystate = currentkeystate;          if (//condition keydown) {             currentkeystate = true;          } else {             currentkeystate = false;         }     }      public static boolean keyreleased() {        if (currentkeystate == true && previouskeystate == false) {             return true;        } else {             return false;         }    } }

here's c# version of i'm trying accomplish. there method similar keyboard.getstate() in java?

using system; using system.collections.generic; using system.linq; using microsoft.xna.framework; using microsoft.xna.framework.input;  namespace game.controls {     public class inputhandler     {     public keyboardstate currentkeystate;     public keyboardstate previouskeystate;      public inputhandler()     {         currentkeystate = new keyboardstate();         previouskeystate = new keyboardstate();     }      public void update()     {         previouskeystate = currentkeystate;         currentkeystate = keyboard.getstate();     }      public bool isheld(keys key)     {         if (currentkeystate.iskeydown(key))         {             return true;         }         else         {             return false;         }     }      public bool isreleased(keys key)     {         if (currentkeystate.iskeyup(key) && previouskeystate.iskeydown(key))         {             return true;         }         else         {             return false;         }     }      public bool ispressed(keys key)     {         if (currentkeystate.iskeydown(key) && previouskeystate.iskeyup(key))         {             return true;         }         else         {             return false;         }     } }

}

if (keyboard.geteventkey() == keyboard.key_a) {     if (keyboard.geteventkeystate()) {         system.out.println("a key pressed");     }     else {         system.out.println("a key released");     } }

you can refer this document

for getting input methods.

for keys supported refer http://www.lwjgl.org/javadoc/org/lwjgl/input/keyboard.html


Comments

Post a Comment

Popular posts from this blog

django - How can I change user group without delete record -

-
on website user have 1 group. , user can change group. it's made user.groups.clear() and user.groups.add(new_group) but it's not efficient, because there 2 sql query: delete, insert. how can change group update query? user , group related each other using manytomanyfield . means intersection table exists relating both entities, , if don't specify model map (using through attribute) django creates 1 you. looking @ sources django.contrib.auth.models see that's case. fortunatly, can access intermediary model using through attribute of manager (in case, user.groups.through ). can use regular model. example: >>> alice = user.objects.create_user('alice', 'alice@example.com', 'alicepw') >>> employee = group.objects.create(name='employee') >>> manager = group.objects.create(name='manager') >>> alice.groups.add(employee) >>> alice.groups.all() [<group: employee...
Read more

java - Need to add SOAP security token -

-
i need set custom soap header attribute on jax-ws generated webservice client. case webservice calls must go through proxy server requiring specific token (recieved web request header) present in soap request header. e.g.: 1 carserviceservice service = null; 2 service = new carserviceservice(new url(url), new qname(qname); 3 carserviceendpoint port = service.getcarserviceport(); it seems in line 3 wsdl retrieved , call fails due missing security token. 1 point direction on how done? a detailed example has been mentioned here: creating , deploying jax-ws web service on tomcat 6 this article shows how create , use security token .
Read more

java - EclipseLink JPA Object is not a known entity type -

-
i have strange problem eclipselink , object want persist. have 1 object (keypointlistimpl) stores object keypointimpl in list. persisting keypointimpl objects works great if try persist keypointlistimpl object java.lang.illegalargumentexception says object keypointimpl isn't known entity type. here keypointimpl code: @entity @table(name="keypoints") public class keypointimpl implements keypoint { @id @generatedvalue(strategy = generationtype.identity) private int id; @enumerated(enumtype.string) private detectortype keypointtype; private float x; private float y; private float size; private float angle; private float response; private int octave; private int classid; ... } here keypointlistimpl code: @entity @table(name="keypointlists") public class keypointlistimpl implements keypointlist { @id @generatedvalue(strategy = generationtype.identity) private int id; @onetoone(cascade={ca...
Read more