php - How to resolve error in my sql manual? -

-

i encounter error in sql in running program, how can resol error?

error: have error in sql syntax; check manual corresponds mysql server version right syntax use near 's', 's', 's','s','s','s','s', 's')' @ line 3

this syntax used.

<?php      include('config.php');     error_reporting("e_all"); ?> <html xmlns="http://www.w3.org/1999/xhtml"> <html xmlns="http://www.w3.org/1999/xhtml"> <head>     <meta http-equiv="content-type" content="text/html; charset=utf-8" />     <title>avaya</title>     <link rel="stylesheet" href="css/style.css" type="text/css" media="screen" />  </head> <body> <div id="page" class="shell"> <div id="mainwrapper">  <div id="top">         <div class="cl">&nbsp;</div>         <h1><img src="css/images/dtsi-logo.jpg"></h1>         <div class="cl">&nbsp;</div> <div> <?php include_once("template_header.php");?> </div>      </div>  <?php $host="localhost"; // host name  $username="<myusername>"; // mysql username  $password="<mypassword>"; // mysql password  $db_name="inventory"; // database name  $tbl_name="avaya_pabx"; // table name  mysql_connect("$host", "$username", "$password")or die("cannot connect");  mysql_select_db("$db_name")or die("cannot select db");   $con = mysql_connect("localhost","root",""); if (!$con)   {   die('could not connect: ' . mysql_error());   } mysql_select_db("inventory", $con);   $addavaya="insert avaya_pabx (item_no, critical_spare_id, serial_no, comcode, version, circuit_pack, classification, location, availability) values ('". $_post['item_no'] . ", '". $_post['critical_spare_id'] . "', '" . $_post['serial_no']. "', '". $_post['comcode'] . "','". $_post['version'] . "','". $_post['circuit_pack'] . "','". $_post['classification'] . "','". $_post['location'] . "', '". $_post['availability'] . "')";   $result = mysql_query($addavaya,$con);  if (!$result)    {   die('error: ' . mysql_error());   } echo "1 record added";  mysql_close($con);  ?>  <br /><a href='avayatable.php'><input type=button class='classname' value='back'></a>  <?php include_once("template_footer.php");?> </div> <br />  </div> </body> </html>

hello sql injection ...

try use pdo instead of approach

http://php.net/manual/en/book.pdo.php

however, solution problem first variable in values must this

 values ('". $_post['item_no'] . "',

Comments

Post a Comment

Popular posts from this blog

django - How can I change user group without delete record -

-
on website user have 1 group. , user can change group. it's made user.groups.clear() and user.groups.add(new_group) but it's not efficient, because there 2 sql query: delete, insert. how can change group update query? user , group related each other using manytomanyfield . means intersection table exists relating both entities, , if don't specify model map (using through attribute) django creates 1 you. looking @ sources django.contrib.auth.models see that's case. fortunatly, can access intermediary model using through attribute of manager (in case, user.groups.through ). can use regular model. example: >>> alice = user.objects.create_user('alice', 'alice@example.com', 'alicepw') >>> employee = group.objects.create(name='employee') >>> manager = group.objects.create(name='manager') >>> alice.groups.add(employee) >>> alice.groups.all() [<group: employee...
Read more

java - Need to add SOAP security token -

-
i need set custom soap header attribute on jax-ws generated webservice client. case webservice calls must go through proxy server requiring specific token (recieved web request header) present in soap request header. e.g.: 1 carserviceservice service = null; 2 service = new carserviceservice(new url(url), new qname(qname); 3 carserviceendpoint port = service.getcarserviceport(); it seems in line 3 wsdl retrieved , call fails due missing security token. 1 point direction on how done? a detailed example has been mentioned here: creating , deploying jax-ws web service on tomcat 6 this article shows how create , use security token .
Read more

java - EclipseLink JPA Object is not a known entity type -

-
i have strange problem eclipselink , object want persist. have 1 object (keypointlistimpl) stores object keypointimpl in list. persisting keypointimpl objects works great if try persist keypointlistimpl object java.lang.illegalargumentexception says object keypointimpl isn't known entity type. here keypointimpl code: @entity @table(name="keypoints") public class keypointimpl implements keypoint { @id @generatedvalue(strategy = generationtype.identity) private int id; @enumerated(enumtype.string) private detectortype keypointtype; private float x; private float y; private float size; private float angle; private float response; private int octave; private int classid; ... } here keypointlistimpl code: @entity @table(name="keypointlists") public class keypointlistimpl implements keypointlist { @id @generatedvalue(strategy = generationtype.identity) private int id; @onetoone(cascade={ca...
Read more